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pavank

data _null_; string = 'antioxidant'; length unique $200 position_list $200; do i = 1 to length(string); letter = substr(string, i, 1); count = countc(string, letter); if count = 1 then do; unique = cats(unique, letter); position_list = cats(position_list, i); end; end; put unique; put position_list; run; I want output position of non repeated letters like below Non-Repeated_Letters O X D antioxidant 5 6 8

jaliu · ‎08-29-2021

I'm kind of confused about what a library is. I think it's just a folder that contains folders and files, but this is not clear to me. If a library doesn't have any files (but rather has files in subfolders), will files not be accessible? Would we/can therefore add another libref to a subfolder to access those files within subfolders?

Arjayita

Hello all, I am very new to SAS. I can interpret a few things in SAS but when it comes to writing a code I am completely lost. data dormant_pca_cc; set dev.fcs_jun19_dorm_pca_cc_build; Above is my dataset info. Attached is the file containing the final variables(along with variable description) which should be considered for calculating obligator level score/ PD. The dependent variable is: FCS_bad_9m_Jun19 Can anyone help me writing a code to calculate obligator level PD in SAS? Many thanks, A

kcvaldez98

Hi SAS Coders: I am trying to change numeric observations into character so I can do my analysis, but it is showing blank observations for these variables: Obs fast purge language age_group sex_category ethnicity USBorn slimfast DescribeWt HomeEnv 1 . . E <11 Male NonH Life No VeryOver PrettyT 2 . . E <11 Male NonH Life No SlghtOve VeryTru 3 . . E <11 Male Hisp Miss Mis Right Missing 4 . . E <11 Female NonH Life No Right VeryTru 5 . . E <11 Male Hisp Life No SltUnder PrettyT 6 . . E <11 Female Hisp Life No Right VeryTru 7 . . E <11 Female NonH Life No Right PrettyT 8 . . E <11 Female NonH Life No SlghtOve PrettyT 9 . . E <11 Female NonH Life No SltUnder VeryTru 10 . . E <11 Female NonH Life No Right VeryTru I know the observations are in fact numeric as it says "1" and "2" in the dataset My code is this: DATA WORK.CLEANDATA; SET YRRSIMPT.import; /* Categorize age */ IF age < 11 THEN age_group = "<11"; ELSE IF age = 12 THEN age_group = "12"; ELSE IF age = 13 THEN age_group = "13"; ELSE IF age = 14 THEN age_group = "14"; ELSE IF age >= 15 THEN age_group = "14+"; ELSE age_group = "Missing"; /* Categorize sex */ IF sex = 1 THEN sex_category = "Female"; ELSE IF sex = 2 THEN sex_category = "Male"; ELSE sex_category = "Missing"; IF v4 = 1 THEN ethnicity = "Hisp"; ELSE IF v4 = 2 THEN ethnicity = "NonHisp"; ELSE ethnicity = "Missing"; /* Categorize v66 (USBorn) */ IF v66 = 1 THEN USBorn = "<1Yr"; ELSE IF v66 = 2 THEN USBorn = "1-3Yrs"; ELSE IF v66 = 3 THEN USBorn = "4-6Yrs"; ELSE IF v66 = 4 THEN USBorn = "6+Yr"; ELSE IF v66 = 5 THEN USBorn = "Life"; ELSE USBorn = "Missing"; /* Categorize v51 */ IF v51 = 1 THEN fast = "Yes"; ELSE IF v51 = 2 THEN fast = "No"; ELSE fast = "Missing"; /* Categorize v52 */ IF v52 = 1 THEN purge = "Yes"; ELSE IF v52 = 2 THEN purge = "No"; ELSE purge = "Missing"; /* Categorize v53 */ IF v53 = 1 THEN slimfast = "Yes"; ELSE IF v53 = 2 THEN slimfast = "No"; ELSE slimfast = "Missing"; IF v49 = 1 THEN DescribeWt = "VUnderWt"; ELSE IF v49 = 2 THEN DescribeWt = "SltUnder"; ELSE IF v49 = 3 THEN DescribeWt = "Right"; ELSE IF v49 = 4 THEN DescribeWt = "SlghtOver"; ELSE IF v49 = 5 THEN DescribeWt = "VeryOver"; ELSE DescribeWt = "Missing"; /* Categorize v71 (HomeEnv) */ IF v71 = 1 THEN HomeEnv = "NotTrue"; ELSE IF v71 = 2 THEN HomeEnv = "LilTrue"; ELSE IF v71 = 3 THEN HomeEnv = "PrettyTrue"; ELSE IF v71 = 4 THEN HomeEnv = "VeryTrue"; ELSE HomeEnv = "Missing"; KEEP age_group ethnicity sex_category HomeEnv purge fast USBorn DescribeWt language slimfast; RUN;

SAS_TSNEWS

A new update is available for SAS Infrastructure for Risk Management , version 3.7 : Hot Fix: M2Q002 - Published 08MAY2024 , Download link for M2Q002 Component name: SAS Infrastructure for Risk Management Related SAS release: 9.4 Issues addressed in M2Q002 SAS Note 70538 SAS® Infrastructure for Risk Management tables are not updated to reflect configurable inputs SAS Note 70539 An error occurs when deleting instances from the SAS® Infrastructure for Risk Management User Interface SAS Note 70540 The SAS® Infrastructure for Risk Management Live ETL process fails with the error “java.lang.NullPointerException” SAS Note 70541 SAS® Infrastructure for Risk Management instances that are created from personal federated areas have slower performance SAS Note 70610 An HTTP 403 error occurs when running SAS® Infrastructure for Risk Management instances in parallel SAS Note 70612 SAS® Infrastructure for Risk Management batch performance improvements SAS Note 70640 SAS® Infrastructure for Risk Management enables the use of PooledConnectionProvider This list of notes might be incomplete. For a complete list of issues addressed by this hot fix, visit the hot fix page for M2Q002 Note: A comprehensive list of all SAS hot fixes is available from support.sas.com. You can use the SAS Hot Fix Analysis, Download, and Deployment (SASHFADD) tool to manage your SAS hot fixes.