Hi SAS community, I am a novice SAS user. I would like to analyze a dataset from an experiment.  I have tree samples from two trials conducted at different sites. Each site was divided into several blocks, and tree seedlings from 4 origins were randomly planted within each black. 50+ years later, two blocks from each site were selected and 3 trees from each of the origins were harvested. Then each tree was "cut" into wood products using 3 different cutting methods (using a simulation software).  I would like to test if there are differences in product recovery between the two sites, among the origins, and among the cutting methods. 1) I am not interested in blocks, so the block factor will be a random variable. Should I consider trees from each origin as subsampling or as another random factor, or maybe a replication?   2) The analysis I have done so far assumed the trees were randomly select from each origin within each block. What if the trees were randomly selected not at the origin level, but at the block level to cover the full range of tree sizes within the block (tree size have huge effect on recovery)? If this were the case, should I drop origin in the model, because its levels were not considered in the sampling? Here is what I have so far. I am not confident if this is a correct analysis and will be very appreciate if anyone could point me to a correct way to analyze the data (attached).   PROC GLIMMIX data=data; class site origin block cut tree; model recovery = site*origin*cut/ddfm=kr; random block site*origin*cut*block; run;   Thank you very much. Tess ... View more

Well, I know you've been asking yourself, "When is the new SAS developer portal going to launch?" The answer is, it already has.   This marks a significant milestone for the API Developer Experience team as we announce the external launch of the new developers.sas.com (notice the 's' on developers)! It's available now. Go check it out. ... View more

I need to combine same clinic names if the corresponding prior_span =1. For example, if Clinic_name1 and Clinic_name2 where both Clinic A and Prior_span1 and prior_span2 both =1 then Clinic would = A. Clinic_name_1 corresponds with Prior_span1 Clinic_name_2 corresponds with Prior_span2 Clinic_name_3 corresponds with Prior_span3   Below is my sample data.    Thanks! Data Have; input ID$ Clinic_Name_1$ Clinic_Name_2$ Clinic_Name_3$ Prior_Span1$ Prior_Span2$ Prior_Span3$ Cost service$ ; datalines; 1 B A . 0 0 0 168 A 2 A A . 1 0 0 46 B 2 A A . 0 1 0 99 C 3 B . . 0 0 0 24 D 4 D . . 0 0 0 54 A 5 B D F 0 1 0 405 B 7 A . . 1 0 0 90 F 8 E E A 0 0 1 87 J 9 F . . 0 0 0 0 G 10 C C C 0 0 0 40 C 10 C C C 0 0 1 374 B 10 C C C 0 1 1 60 A ; run; ***Summary table-clinic var not created yet****; proc sql; create table want as select 1 as ID1,'service' as a length=40,Clinic, 1 as ID2,put(service, $40.) as b length=40, 1 as ID3,(select count(distinct ID) from have where Clinic=a.Clinic and service=a.service and cost>0 ) as c format=comma20., 1 as ID4,calculated c/(select count(distinct ID) from have where Clinic=a.Clinic and cost>0 ) as d format=percent8.1, 1 as ID5,sum(cost) as e format=dollar20., 1 as ID6,sum(cost)/(select sum(cost) from have where Clinic=a.Clinic) as f format=percent8.1 from have as a group by Clinic,service union all select 7 as id1,'09'x as a,Clinic, 7 as id2,'Total Clients' as b, 7 as id3,count(distinct ID) as f, 7 as id4,., 7 as id5,., 7 as id7,. from have where service ne 'j' and cost>0 group by Clinic union all select 7 as id1,'09'x as a,Clinic, 7 as id2,' Total Cost' as f, 7 as id3,. as c, 7 as id4,., 7 as id5,sum(cost), 7 as id7,. from have where service ne 'j' and cost>0 group by Clinic ;quit; options missing=' '; proc report data=want nowd; column id1 a b Clinic,(c d e f); define id1/group noprint; define a/group noprint ' '; define b/group ' '; define c/analysis 'Clients'; define d/analysis '% of Clients'; define e/analysis 'Cost'; define f/analysis '% of Cost'; define Clinic/across ''; compute before a/style={just=l color=black}; if id1=1 then len=0; else len=10; x=' '; line x $varying10. len; line a $40.; endcomp; run;   ... View more

  DATA ALT; SET RCA.CLOSING_STATUS_TEST; ARRAY COLS[*] _CHARACTER_; ARRAY COLS_[*] _CHARACTER_; DO I = 1 TO DIM(COLS); IF MOD(I, 2) = 1 THEN COLS_[(I+1)/2] = COLS[I]; END; DROP I; RUN; Hi, I have been trying to select the alternate columns. If I am using this code then my third column's data shifts to second column and second's values are disappearing.  I want to select alternate columns from my data set and my column names are in following: LOAN_NO, PRODUCT, FINAL_STATUS_05MAY24,DUE_N_TAG_05MAY24, FINAL_STATUS_06MAY24,DUE_N_TAG_06MAY24, FINAL_STATUS_07MAY24,DUE_N_TAG_07MAY24,... and so on. I want to create a table selecting columns:-  LOAN_NO, FINAL_STATUS_05MAY24, FINAL_STATUS_06MAY24, FINAL_STATUS_07MAY24... and so on. If there is any alternate approach for making the selection, please advise me or please help with the given array code.      ... View more